1928 United States presidential election in Indiana

1928 United States presidential election in Indiana

November 6, 1928
Turnout74.9% 4.2 pp
 
Nominee Herbert Hoover Al Smith
Party Republican Democratic
Home state California New York
Running mate Charles Curtis Joseph T. Robinson
Electoral vote 15 0
Popular vote 848,290 562,691
Percentage 59.7% 39.6%

County Results

President before election

Calvin Coolidge
Republican

Elected President

Herbert Hoover
Republican

A presidential election was held in Indiana on November 6, 1928, as part of the 1928 United States presidential election. The Republican ticket of the U.S. secretary of commerce Herbert Hoover and the senior U.S. senator from Kansas Charles Curtis defeated the Democratic ticket of the governor of New York Al Smith and the senior U.S. senator from Arkansas Joseph T. Robinson. Hoover defeated Smith in the national election with 444 electoral votes.

Indiana was seen as critical to Smith's chances in the national election; however, by early July, observers predicted that the opposition of the politically powerful Indiana Ku Klux Klan and the Anti-Saloon League would make it impossible for Smith to carry the state. Hoover blamed Democrats and the Federal Reserve System for the interwar farm crisis in a campaign visit to Indiana in late August, but the Indiana Farm Bureau did not endorse either ticket. Smith's Catholicism, opposition to Prohibition, and association with Tammany Hall alienated progressives who branded the candidate as a "patron of gambling and vice." Anti-Catholic dog whistles marked the Republican campaign in Indiana, leading Protestants across denominational lines to vote for Hoover. Hoover's national surrogates warned that Smith would "flood the nation with unsavory immigrants," create an epidemic of alcoholism, and open the path to state socialism. When Smith's train crossed into Indiana, he was greeted by a burning cross visible from the window of his car.