1824 United States presidential election in Indiana
November 8, 1824
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| Turnout | 37.1% | ||||||||||||||||||||||||||||||||
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County Results
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| Elections in Indiana |
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A presidential election was held in Indiana on November 8, 1824, as part of the 1824 United States presidential election. The junior U.S. senator from Tennessee Andrew Jackson defeated the speaker of the U.S. House of Representatives Henry Clay and the U.S. secretary of state John Quincy Adams. All three candidates represented the Democratic-Republican Party. No candidate won a majority of the electoral vote in the national election; Adams eventually became the 6th president of the United States after winning a contingent election conducted by the United States House of Representatives.
This was the first election in which Indiana's electors were elected by voters statewide, rather than by appointment of the state legislature. Jackson was nominated by delegates to a convention held at Salem, Indiana, and drew support based on his military record, residence in a Western state, support for internal improvements, and fidelity to republican principles. Clay hoped to carry the state based on his advocacy for Western interests, but was harmed by closeness to political elites blamed for the lingering economic recession. Adams was popular with Quakers and others opponents of slavery, but perceived indifference to the need for regional economic development limited his appeal. Jackson carried the state with a plurality based on his strength in Southern Indiana, while Clay won most of the sparsely-populated counties in Central Indiana. Adams ran a distant third in much of the state, but carried Randolph and Wayne counties, home to the Quaker stronghold of Richmond, Indiana.