1990 United States Senate election in Rhode Island

1990 United States Senate election in Rhode Island
November 6, 1990
 
Nominee Claiborne Pell Claudine Schneider
Party Democratic Republican
Popular vote 225,105 138,947
Percentage 61.83% 38.17%
County results
Pell:      50–60%      60–70%      70–80%
Schneider:      50–60%
U.S. senator before election

Claiborne Pell
Democratic

Elected U.S. Senator

Claiborne Pell
Democratic

The 1990 United States Senate election in Rhode Island was held on November 6, 1990, to select the U.S. senator from the state of Rhode Island. Incumbent Democratic Senator Claiborne Pell won a sixth and final term, defeating Republican challenger Representative Claudine Schneider of Rhode Island's 2nd congressional district. Both candidates were popular in the state, winning their respective primaries unopposed. A large issue in the race was Pell's age, especially following a poor debate performance. Schneider refused to run a negative campaign and avoided attacking Pell, instead emphasizing her opposition to taxes and her "tough on crime" stance.

Rhode Island was seen as one of the most important battlegrounds in the 1990 Senate cycle. The election had a turnout rate of over 40%. Despite being considered among the most vulnerable Democrats, Pell won in a landslide with over 61% of the vote and winning all of the state's counties. However, his margin of victory decreased from 1984.

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