1812 United States presidential election in Rhode Island

Main article: 1812 United States presidential election
1812 United States presidential election in Rhode Island
October 30 – December 2, 1812
 
Nominee DeWitt Clinton James Madison
Party Democratic-Republican Democratic-Republican
Alliance Federalist  –
Running mate Jared Ingersoll Elbridge Gerry
Electoral vote 4 0
Popular vote 4,032 2,084
Percentage 65.93% 34.07%
President before election

James Madison
Democratic-Republican

Elected President

James Madison
Democratic-Republican

The 1812 United States presidential election in Rhode Island took place as part of the 1812 United States presidential election. Voters chose four representatives, or electors, to the Electoral College, who voted for president and vice president.

Rhode Island voted for the Democratic-Republican and Federalist supported candidate, DeWitt Clinton, over normal Democratic-Republican candidate, incumbent President James Madison. Clinton won Rhode Island by a margin of 65.93%. With Madison's second loss (the first one was 1808), this marked the first time that a candidate or an incumbent president lost two presidential elections in Rhode Island.

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