1869 Iowa gubernatorial election

1869 Iowa gubernatorial election
October 12, 1869
 
Nominee Samuel Merrill George Gillespie
Party Republican Democratic
Popular vote 97,243 57,287
Percentage 62.93% 37.07%
County results
Merrill:      50–60%      60–70%      70–80%      80–90%      90–100%
Gillespie:      50–60%      60–70%
No Data/Votes:      
Governor before election

Samuel Merrill
Republican

Elected Governor

Samuel Merrill
Republican

The 1869 Iowa gubernatorial election was held on October 12, 1869. Incumbent Republican Samuel Merrill defeated Democratic nominee George Gillespie with 62.93% of the vote.

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