1867 Iowa gubernatorial election

1867 Iowa gubernatorial election
October 8, 1867
 
Nominee Samuel Merrill Charles Mason
Party Republican Democratic
Popular vote 90,204 62,966
Percentage 58.88% 41.10%
County results
Merrill:      50–60%      60–70%      70–80%      80–90%      90–100%
Mason:      50–60%      60–70%
No Data/Votes:      
Governor before election

William M. Stone
Republican

Elected Governor

Samuel Merrill
Republican

The 1867 Iowa gubernatorial election was held on October 8, 1867. Republican nominee Samuel Merrill defeated Democratic nominee Charles Mason with 58.88% of the vote.

This article is issued from Wikipedia. The text is available under Creative Commons Attribution-Share Alike 4.0 unless otherwise noted. Additional terms may apply for the media files.