Pascoag, Rhode Island
Pascoag, Rhode Island | |
|---|---|
Census-designated place | |
Pascoag c. 1900 | |
Location in Providence County, Rhode Island | |
| Coordinates: 41°57′27″N 71°42′21″W / 41.95750°N 71.70583°W | |
| Country | United States |
| State | Rhode Island |
| County | Providence |
| Area | |
• Total | 5.56 sq mi (14.41 km2) |
| • Land | 5.07 sq mi (13.13 km2) |
| • Water | 0.49 sq mi (1.28 km2) |
| Elevation | 430 ft (130 m) |
| Population (2020) | |
• Total | 4,641 |
| • Density | 915.5/sq mi (353.48/km2) |
| Time zone | UTC-5 (Eastern (EST)) |
| • Summer (DST) | UTC-4 (EDT) |
| ZIP code | 02859 |
| Area code | 401 |
| FIPS code | 44-54460 |
| GNIS feature ID | 1218912 |
Pascoag (PASS-ko or PASS-kog) is a census-designated place (CDP) and village in Providence County, Rhode Island, United States. As of the 2020 census, Pascoag had a population of 4,641. Pascoag is one of eight villages that make up the town of Burrillville.