Jackson Township, Dallas County, Arkansas
Jackson Township | |
|---|---|
Jackson Township Location in Arkansas Jackson Township Jackson Township (the United States) | |
| Coordinates: 33°50′48″N 92°31′59″W / 33.846733°N 92.532990°W | |
| Country | United States |
| State | Arkansas |
| County | Dallas |
| Area | |
• Total | 35.844 sq mi (92.84 km2) |
| • Land | 35.839 sq mi (92.82 km2) |
| • Water | 0.005 sq mi (0.013 km2) |
| Elevation | 292 ft (89 m) |
| Population (2010) | |
• Total | 190 |
| • Density | 5.3/sq mi (2.0/km2) |
| Time zone | UTC-6 (CST) |
| • Summer (DST) | UTC-5 (CDT) |
| FIPS code | 05-91860 |
| GNIS ID | 66488 |
Jackson Township is a township in Dallas County, Arkansas, United States. Its total population was 190 as of the 2010 United States census, a decrease of 18.10 percent from 232 at the 2000 census.
According to the 2010 Census, Jackson Township is located at 33°50′48″N 92°31′59″W / 33.846733°N 92.532990°W (33.846733, -92.532990). It has a total area of 35.844 square miles (92.84 square kilometers); of which 35.839 sq mi (92.82 km2) is land and 0.005 sq mi (0.013 km2) is water (0.01%). As per the USGS National Elevation Dataset, the elevation is 292 feet (89 m).