Harlan Township, Fayette County, Iowa
Harlan Township | |
|---|---|
Location in Fayette County | |
| Coordinates: 42°46′51″N 91°54′45″W / 42.78083°N 91.91250°W | |
| Country | United States |
| State | Iowa |
| County | Fayette |
| Area | |
• Total | 36.79 sq mi (95.28 km2) |
| • Land | 36.76 sq mi (95.22 km2) |
| • Water | 0.027 sq mi (0.07 km2) 0.07% |
| Elevation | 1,145 ft (349 m) |
| Population (2010) | |
• Total | 871 |
| • Density | 23.7/sq mi (9.15/km2) |
| Time zone | UTC-6 (CST) |
| • Summer (DST) | UTC-5 (CDT) |
| ZIP codes | 50655, 50662, 50681, 52142, 52164 |
| GNIS feature ID | 0468005 |
Harlan Township is one of twenty townships in Fayette County, Iowa. As of the 2010 census, its population was 871.