Andrew, Iowa
Andrew, Iowa | |
|---|---|
Location of Andrew, Iowa | |
| Coordinates: 42°09′12″N 90°35′32″W / 42.15333°N 90.59222°W | |
| Country | United States |
| State | Iowa |
| County | Jackson |
| Incorporated | August 4, 1863 |
| Area | |
• Total | 0.25 sq mi (0.64 km2) |
| • Land | 0.25 sq mi (0.64 km2) |
| • Water | 0 sq mi (0.00 km2) |
| Elevation | 883 ft (269 m) |
| Population (2020) | |
• Total | 380 |
| • Density | 1,532.5/sq mi (591.69/km2) |
| Time zone | UTC-6 (Central (CST)) |
| • Summer (DST) | UTC-5 (CDT) |
| ZIP code | 52030 |
| Area code | 563 |
| FIPS code | 19-02125 |
| GNIS feature ID | 2393957 |
Andrew is a town in central Jackson County, Iowa, United States. The population was 380 at the 2020 census.